Searched refs:bigFivePows (Results 1 – 2 of 2) sorted by relevance
63 static final BigInteger bigFivePows[] = new BigInteger[32]; field in Multiplication72 bigFivePows[i] = BigInteger.valueOf(fivePow);77 bigFivePows[i] = bigFivePows[i - 1].multiply(bigFivePows[1]);135 res = bigFivePows[1].pow(intExp).shiftLeft(intExp); in powerOf10()144 BigInteger powerOfFive = bigFivePows[1].pow(Integer.MAX_VALUE); in powerOf10()153 res = res.multiply(bigFivePows[1].pow(intExp)); in powerOf10()181 } else if (exp < bigFivePows.length) { in multiplyByFivePow()182 return val.multiply(bigFivePows[exp]); in multiplyByFivePow()184 return val.multiply(bigFivePows[1].pow(exp)); in multiplyByFivePow()
193 FIVE_POW = Multiplication.bigFivePows;