Searched refs:lastBreakableBegin (Results 1 – 1 of 1) sorted by relevance
149 auto lastBreakableBegin = *wordStart; in findLongestWordSequence() local155 lastBreakableBegin = *wordStart; in findLongestWordSequence()200 } else if (*rangeBegin != lastBreakableBegin) { in findLongestWordSequence()202 resultRange = {**rangeBegin, *lastBreakableBegin}; in findLongestWordSequence()