Searched refs:divRem (Results 1 – 1 of 1) sorted by relevance
998 BigInteger[] divRem = nanos.divideAndRemainder(BI_NANOS_PER_SECOND); in create() local999 if (divRem[0].bitLength() > 63) { in create()1002 return ofSeconds(divRem[0].longValue(), divRem[1].intValue()); in create()