Searched refs:adj0 (Results 1 – 1 of 1) sorted by relevance
351 double adj0, tol; local947 adj0 = dval(&adj) = 1.;950 adj0 = dval(&adj) *= 0.5;956 L = adj0;957 adj0 -= L;960 if (adj0 >= .5)964 if (asub && adj0 > 0.)968 if (!asub && adj0 > 0.) {1055 dval(&adj) = adj0 - .5;1057 if (adj0 > tol) {[all …]