Searched refs:a20 (Results 1 – 3 of 3) sorted by relevance
786 double a20 = m[6]; in invert() local793 double t10 = a20 * a12 - a10 * a22; in invert()794 double t11 = a00 * a22 - a20 * a02; in invert()796 double t20 = a10 * a21 - a20 * a11; in invert()797 double t21 = a20 * a01 - a00 * a21; in invert()
475 Target.Floaty a20 = t.multiply(t.newFloaty(v1[2]), t.newFloaty(v2[0])); in cross() local476 out[1] = t.subtract(a20, a02); in cross()491 Target.Floaty a20 = t.multiply(t.new32(v1[2]), t.new32(v2[0])); in cross() local492 out[1] = t.subtract(a20, a02); in cross()
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