1 /* 2 * Copyright (C) 2008 The Android Open Source Project 3 * 4 * Licensed under the Apache License, Version 2.0 (the "License"); 5 * you may not use this file except in compliance with the License. 6 * You may obtain a copy of the License at 7 * 8 * http://www.apache.org/licenses/LICENSE-2.0 9 * 10 * Unless required by applicable law or agreed to in writing, software 11 * distributed under the License is distributed on an "AS IS" BASIS, 12 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 13 * See the License for the specific language governing permissions and 14 * limitations under the License. 15 */ 16 17 import java.util.Arrays; 18 import java.util.LinkedList; 19 20 /** 21 * Exercise the construction and throwing of OutOfMemoryError. 22 */ 23 public class Main { main(String args[])24 public static void main(String args[]) { 25 System.out.println("tests beginning"); 26 testHugeArray(); 27 testOomeLarge(); 28 testOomeSmall(); 29 testOomeToCharArray(); 30 System.out.println("tests succeeded"); 31 } 32 testHugeArray()33 private static void testHugeArray() { 34 try { 35 final int COUNT = 32768*32768 + 4; 36 int[] tooBig = new int[COUNT]; 37 38 Arrays.fill(tooBig, 0xdd); 39 } catch (OutOfMemoryError oom) { 40 System.out.println("Got expected huge-array OOM"); 41 } 42 } 43 testOomeLarge()44 private static void testOomeLarge() { 45 System.out.println("testOomeLarge beginning"); 46 47 Boolean sawEx = false; 48 byte[] a; 49 50 try { 51 // Just shy of the typical max heap size so that it will actually 52 // try to allocate it instead of short-circuiting. 53 a = new byte[(int) Runtime.getRuntime().maxMemory() - 32]; 54 } catch (OutOfMemoryError oom) { 55 //Log.i(TAG, "HeapTest/OomeLarge caught " + oom); 56 sawEx = true; 57 } 58 59 if (!sawEx) { 60 throw new RuntimeException("Test failed: " + 61 "OutOfMemoryError not thrown"); 62 } 63 64 System.out.println("testOomeLarge succeeded"); 65 } 66 67 /* Do this in another method so that the GC has a chance of freeing the 68 * list afterwards. Even if we null out list when we're done, the conservative 69 * GC may see a stale pointer to it in a register. 70 */ testOomeSmallInternal()71 private static boolean testOomeSmallInternal() { 72 final int LINK_SIZE = 6 * 4; // estimated size of a LinkedList's node 73 74 LinkedList<Object> list = new LinkedList<Object>(); 75 76 /* Allocate progressively smaller objects to fill up the entire heap. 77 */ 78 int objSize = 1 * 1024 * 1024; 79 while (objSize >= LINK_SIZE) { 80 boolean sawEx = false; 81 try { 82 for (int i = 0; i < Runtime.getRuntime().maxMemory() / objSize; i++) { 83 list.add((Object)new byte[objSize]); 84 } 85 } catch (OutOfMemoryError oom) { 86 sawEx = true; 87 } 88 89 if (!sawEx) { 90 return false; 91 } 92 93 objSize = (objSize * 4) / 5; 94 } 95 96 return true; 97 } 98 testOomeSmall()99 private static void testOomeSmall() { 100 System.out.println("testOomeSmall beginning"); 101 if (!testOomeSmallInternal()) { 102 /* Can't reliably throw this from inside the internal function, because 103 * we may not be able to allocate the RuntimeException. 104 */ 105 throw new RuntimeException("Test failed: " + 106 "OutOfMemoryError not thrown while filling heap"); 107 } 108 System.out.println("testOomeSmall succeeded"); 109 } 110 testOomeToCharArray()111 private static void testOomeToCharArray() { 112 Object[] o = new Object[2000000]; 113 String test = "test"; 114 int i = 0; 115 try { 116 for (; i < o.length; ++i) o[i] = new char[1000000]; 117 } catch (OutOfMemoryError oom) {} 118 try { 119 for (; i < o.length; ++i) { 120 o[i] = test.toCharArray(); 121 } 122 } catch (OutOfMemoryError oom) { 123 o = null; 124 System.out.println("Got expected toCharArray OOM"); 125 } 126 } 127 } 128